Modern Algebra I

Modern Algebra II, Math 4613 and 5003, Section 001, Fall 2007

Syllabus Office hours: Mon,Wedn 1:30-3;Tu, Th 12-1:30.

Final exam solutions

Final Exam on Tuesday, April 29, 10 am in class.

HW 9 Solutions

Hw 9 (Due Friday April 25): 13.4: 1,3; 13.5: 2,5.

Hints: 13.4, #1, very similar to example in class, find all complex roots of x^4-2 and show the splitting field is generated by

2 elements over Q, then apply techniques from class to count the degree.

#3, note x^6-1=(x^2-1)(x^4+x^2+1), this should help to find the complex roots, and for degree note x^4+x^2+1 is not irreducible.

13.5, #2, to find irreducible polynomials check for roots in F_2 and for degree 4 use the fact that

there is only one irreducible polynomial of degree 2; #5, using 1st approach note that [F_p(alpha):F_p] is the degree of irreducible polynomial dividing x^p-x+a, show that every irreducible factor has the same degree and find contradiction.

HW 8 Solutions

Hw 8 (Due Friday April 18): 13.1: #1,8; 13.2: #4,5,14; 13.3: #4.

Hints: #1 is similar to Example (4) in the book; 13.2: #4, 1st one is easy, for the second show Q(1+2^(1/3)+4^(1/3)) is included

in Q(2^(1/3)) and 1+2^(1/3)+4^(1/3) is not in Q (why? use basis), then apply tower law.

#5 show that x^3-2 does not have a root in Q(i), note i=sqrt(-1) is a root of x^2+1, so we know degree of Q(i) over Q,

then use tower law.

#14, Note F(alpha^2) subfield of F(alpha). Use the fact that alpha is a root of polynomial x^2-alpha^2 from F(\alpha^2)[x],

then apply tower law.

Exam 2 solutions

Exam 2 is on Friday, April 11, 9:05 am. (covers sections on modules 10.1-10.4, 12.1)

HW 7 Solutions

Homework 7 (Due April 7): 12.1, #1,2,5,7,8; Sec 10.4: #2,27.

Hints: 12.1, all hints in the book; for #7, you can assume that direct sum is direct product, show that isomorphism as R-modules; for #8, one possibility is to solve the problem when B=Rb (generated by b), you will need to use the property of

PID: nonzero prime ideal is maximal, then relate Ann(B) to Ann(Rb).

10.4, #2, to show nonzero construct nonzero homomorphism from the second Z-module to Z/2Z.

27(d), C-algebra has an induced structure of C-module (check definition), you need to show Phi is C-linear (C-module homomorphism).

Some HW 5-6 Solutions

Homework 6 (Due Wed March 12): 10.3: #4,5,7,11,12,13.

Hints: #4, to give example look for a quotient of rational numbers Q or anything similar;

#5, for each generator of m_i of M there is such r_i, construct r from these; example from #4 will work here;

7, need to show that every element in M is a linear combination of a finite # of elements; construct these elements explicitly form the generators of N and M/N.

11, follow the book hint; for 2nd part, note that isomorphism has inverse homomorphism.

12, explicitly construct natural homomorphisms; for instance in part (a), send map \phi: A\times B -- >M to the pair

(\phi_1, phi_2) such that \phi_1(a)=\phi(a,0), \phi_2(b)=\phi(0,b). Check that you get R-module isomorphism.

Similarly try part (b).

13, assume F=R^n then apply 12(a) and #10 from previous section or try to construct explicitly the map like in 12(a).

Homework 5 (Due Wed. March 5): 10.1: 8,9,10,11; 10.2: 6,8,10.

Hints: 8(b), there are plenty of examples, try R=Z/6Z; 9, do not assume that R is commutative; 11(b) every finite abelian group is a direct product of cyclic groups; first, compute annihilator explicitly as an abelian subgroup of M;

10.1,#6 as in class construct homomorphism Z -- >Hom(Z/nZ,Z/mZ), show: well-defined, surjective, ker=...

10, R commutative with 1, consider map R-- > Hom (R,R), r maps to linear map which is multiplication by r.

Exam 1 solutions

Exam 1 is on Friday, Feb 22. Extra problems for review

Homework 4 (Due Mon Feb 18): Sec 9.3, #1,3; Sec 9.4, #9,11,13,14.

Hints: Hints: 9.3, #1, Read the end of Section 9.3 (a monic polynomial

leading coefficient = 1). Restate equivalently: Suppose R is UFD,

p(x)=a(x)b(x) in R[x] with a(x),b(x) in F[x] monic, then show that

a(x) and b(x) in R[x]. (As in class a(x)=r*a'(x), b(x)=s*b'(x)

where a'(x),b'(x) in R[x] with GCD of coeffic. =1, and r,s in F

with r*s in R. Why r,s must be in R? Think about the case R=Z

integers, F=Q rationals. With Z[2sqrt(2)]={a+b2sqrt(2)|a,b\in Z}

show that its field of fractions is Q[2sqrt(2)]={a+bsqrt(2)|a,b\in

Q} (just consider inverses in real numbers and check that sqrt(2)

in Q[2sqrt(2)]), then factor x^2-2 in Q[2sqrt(2)][x].

 

#3, Why x^2 and x^3 are irreducible in R?

 

9.4, #9 First show that sqrt(2) is irreducible in Z[sqrt(2)] using

norm N(a+b*sqrt(2))=a^2-2b^2 which is multiplicative (we did

similar calculations in Z[\sqrt(-5)]. To show irreducibility of

x^2-\sqrt(2) either use the fact Z[sqrt(2)] is UFD, whence

irreducible is prime and apply Eisenstein's Criterion Another way:

assume reducibility x^2-\sqrt(2)=(x-A)(x-B) with A,B in Z[sqrt(2)]

(Explain why you can do this way), and use the norm to get a

contradiction.

#11, Apply Eisenstein to Q[y][x]; #13, apply rational roots

criterion (proposition 11); #14 Techniques of factorization of low

degree polynomials covered in class, you must show that the

factors are irreducible by using all available criteria.

 

HW 3 Solutions

Homework 3 (Due Wedn, Feb 6): Sec 8.3, #6(a,b),8(a,b), Sec 9.1,#7,13,17,

Sec 9.2, #3,7.

Hints: 8.3,#6(a), reduce cosets using 1+i=0 and i^2=-1 as in

class; 6(b), need to show that Z[i]/(q) has exactly q^2 elements

(similar to part (a)), then show that q is prime in Z[i] by

propositions in class, deduce that (q) is maximal. 8(a), we

showed in class: 1+sqrt(-5) is irreducible (you can skip it),

similarly do the rest, second part is just an obvious statement

that factorization in R is not unique (not UFD); 8(b), we showed

I_2 is prime (skip it), similarly do I_3 and I'_3 (or use hint in

the book); 9.1, 7: try example in #6; 13, one is an integral

domain and the other one is not, show that map F[x,y]-- > F[y], x-->y^2, y-->y,

induces isomorphism of F[x,y]/(x-y^2) onto F[y],

to show injectivity prove that every coset is uniquely represented

by a polynomial dependent on y only. 17, we'll do some part in

class; 9.2,#7 reducing mod 2 and using x^3=-1 show that there are

precisely 8 cosets, whence there is only a finite number of

possible ideals, find all the distinct ideals (how many?), you

should be able to work yourself with such a small ring.

HW 2 Solutions

Homework 2 (Due Mon Jan 28): Sec 7.5, #2,3; Sec 7.6, #1,3; Sec 8.1, #7,10; Sec 8.2, #2,8.

Hints: 7.5, #2 quotient field is field of fractions S^{-1}R with

S=R\{0}, construct natural homomorphism from D^{-1}R to

S^{-1}R, show it's well-defined, injective;

#3 you can use Exercise 26 and 28 (sec7.3) giving 2 cases

F is of prime characteristic p or of characteristic 0.

In 1st case p*1:= 1+...+1=0 (p times)

in field F, and F_0 should contain p elements (explicitly describe

them). Similarly, if F has characteristic 0, then m=1+...+1 (m

times) is never 0. Desribe elements of F_0 explicitly.

For uniqueness note that a subfield of F should always contain 0 and 1

from F. 7.6, #1, R need not to be commutative. Show that the map

Re x R(1-e) --> R, (x_1e,x_2(1-e))--> x_1e+x_2(1-e) is a bijective

homorphism. 8.1,#10, use the hint in the book and then show that

infinite sequence with N(a_1)=N(a_2)=N(a_3)=...and representatives

a _i of distinct cosets of I is not possible (recall N(a)=|a|^2).

HW 1 Solutions

Homework 1 (Due Jan.16): Sec 7.3, #24,34,35; Sec 7.4, #10,11,37

Hints: 7.3, 24 straightforward, try example in (b) with inclusion homomorphism;

34(c), try integers ring Z; (d) assume R has 1, and write 1=a+b, where a in I, b in J;

35, easy; 7.4, note 0 in P, and do by definitions; 11 easy; 37, assume R has 1, let x be in R\M, consider ideal Rx, note Rx+M=??? and use proposition from class that every proper ideal is contained in a maximal ideal to show that Rx=R, 2nd part is easier.